echo on

n = 100;
A = randn(2*n,n);
b = randn(2*n,1);
cvx_begin
   variable x(n)
   minimize( norm( A*x-b ) )
cvx_end

echo off
n = 100;
A = randn(2*n,n);
b = randn(2*n,1);
cvx_begin
   variable x(n)
   minimize( norm( A*x-b ) )
cvx_end
 
Calling SDPT3: 201 variables, 101 equality constraints
   For improved efficiency, SDPT3 is solving the dual problem.
------------------------------------------------------------

 num. of constraints = 101
 dim. of socp   var  = 201,   num. of socp blk  =  1
*******************************************************************
   SDPT3: Infeasible path-following algorithms
*******************************************************************
 version  predcorr  gam  expon  scale_data
    NT      1      0.000   1        0    
it pstep dstep pinfeas dinfeas  gap      prim-obj      dual-obj    cputime
-------------------------------------------------------------------
 0|0.000|0.000|6.6e+00|1.5e+00|2.5e+02| 0.000000e+00  0.000000e+00| 0:0:00| chol  1  1 
 1|0.957|1.000|2.9e-01|6.6e-03|2.3e+01|-9.691971e+00 -2.045281e+01| 0:0:00| chol  1  1 
 2|1.000|1.000|7.3e-08|6.6e-04|1.4e+00|-8.725326e+00 -1.014181e+01| 0:0:00| chol  1  1 
 3|0.985|0.986|1.8e-08|7.5e-05|2.1e-02|-9.515525e+00 -9.535125e+00| 0:0:00| chol  1  1 
 4|0.989|0.989|5.6e-09|7.4e-06|2.3e-04|-9.527047e+00 -9.527166e+00| 0:0:00| chol  1  1 
 5|0.989|0.989|6.2e-11|8.2e-08|2.5e-06|-9.527175e+00 -9.527176e+00| 0:0:00| chol  1  1 
 6|0.989|0.989|1.0e-12|9.1e-10|2.8e-08|-9.527176e+00 -9.527176e+00| 0:0:00|
  stop: max(relative gap, infeasibilities) < 1.49e-08
-------------------------------------------------------------------
 number of iterations   =  6
 primal objective value = -9.52717641e+00
 dual   objective value = -9.52717642e+00
 gap := trace(XZ)       = 2.81e-08
 relative gap           = 1.40e-09
 actual relative gap    = 7.16e-10
 rel. primal infeas     = 1.00e-12
 rel. dual   infeas     = 9.13e-10
 norm(X), norm(y), norm(Z) = 1.4e+00, 9.6e+00, 1.3e+01
 norm(A), norm(b), norm(C) = 1.4e+02, 2.0e+00, 1.5e+01
 Total CPU time (secs)  = 0.11  
 CPU time per iteration = 0.02  
 termination code       =  0
 DIMACS: 1.0e-12  0.0e+00  3.5e-09  0.0e+00  7.2e-10  1.4e-09
-------------------------------------------------------------------
------------------------------------------------------------
Status: Solved
Optimal value (cvx_optval): +9.52718
 

echo off